Explore BrainMass
Share

Explore BrainMass

    B, H and M due to cylindrical conductor

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    An infinitely long solid cylindrical conductor of radius R carries a free current density J(s) = Cs^3z distributed over its cross section. The z axis is the long axis of the cylinder. The conductor has a permeability 'mu' which does not equal 'mu-0'. Outside the conductor is a vacuum.

    A. Find H, B, M inside the conductor and discern between diamagnetic and paramagnetic materials.
    B. Find H,B,M outside the conductor.
    C. Sketch the situation for diamagnetic and paramagnetic materials.

    © BrainMass Inc. brainmass.com October 10, 2019, 7:10 am ad1c9bdddf
    https://brainmass.com/physics/electricity-magnetism/due-cylindrical-conductor-570410

    Attachments

    Solution Preview

    (A)

    By Ampere's circuital law,
    mu * I = close line Integral [ vector(B) . vector(dl) ]

    At distance 's' (< R) from the axis of the conductor (z direction), draw a circle (Ampere circuit) of radius 's', concentric to the axis and in XY plane:

    Current within the area of interest,
    I = integral (0 to s) [ vector(J) . vector(ds) ]

    => I = integral (0 to s) [ C*s^3 * 2*pi*s*ds] = 2*pi*C*s^5/5 = (2/5)*pi*C*s^5

    Hence, by Ampere's circuital law,

    mu * (2/5)*pi*C*s^5 = B * 2*pi*s [ Because, B will be constant at all ...

    Solution Summary

    Due to an infinitely long straight cylindrical conductor, carrying current, magnetic field is estimated inside and outside the conductor.

    $2.19