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# Average electric field strength and average magnetic field strength

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A laser emits 1.30 1018 photons per second in a beam of light that has a diameter of 1.82 mm and a wavelength of 514.5 nm. Determine average electric field strength and average magnetic field strength. Answer in N/C and T.

##### Solution Summary

The answer is given step-by-step equationally. The average electric field strengths and average magnetic field strengths are determined.

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No. of photons emitted per sec (n) = 1.30*10^(18)
wavelength (l) = 514.5*10^(-9) m
speed of light = c = 3*10^8 m/s
Energy per photon (E) = h*c/l
h = planck's constant = 6.67*10^(-34) J.s
Hence,
E = 6.67*10^(-34)*3*10^8/(514.5*10^(-9))
=&gt; E =6.67*3*10^(-34+8+9)/514.5 = ...

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• MSc , Pune University, India
• PhD (IP), Pune University, India
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