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    Velocities, distances by Law of conservation of Energy.

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    Q. Bouncing a ball:
    Let g be the acceleration of gravity near the Earth's surface. The acceleration of gravity near the surface of the Moon is (approximately) g/6. Using the law of conservation of energy, i.e. the principle of conservation of energy, solve the following.

    (a) Suppose that a ball is dropped from 9 feet above the Earth.
    Taking g = 32 feet/second square, at what speed is the ball traveling as it reaches the Earth?
    (b) Suppose that a ball is drpped from 9 feet above the Moon. At what speed is the ball traveling as it reaches the Moon?
    (c) Suppose that a ball dropped from height he above the Earth's surface strikes the ground with the same speed as a ball dropped from a height hm above the Moon's surface. Calculate hm/he.

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    Solution Preview

    Please see the solution in the attached word file 'Solution_Bouncing_ball_01_by_EnergyConservation.doc'

    The soliution of this problem is very simple. Throughout, you have to note that total energy of the ball ...

    Solution Summary

    The velocities and distances by law of conservation of energy is determined. The acceleration of gravity near the surface are determined.

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