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# Undistorted Sinusoidal Signals in a Diode Circuit

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In the diode shown, the diodes are ideal except that each is modeled by a voltage source of 0.5V in series with a (diode) resistance of rd = 20, when forward biased. A sinusoidal signal Vs with input impedance Rs=100 is connected to the diode circuit. Determine the maximum value of Vs such that Vo remains sinusoidal, with no distortion. Also, find the amplitude of the output signal Vo.
Show how you arrived at your solution.

Maximum value Vs(t)
a. Vs(t) = -5cos(wt)
b. Vs(t) = +5cos(wt)
c. Vs(t) = -5sin(wt)
d. Vs(t) = +9sin(wt)

Amplitude of the output signal Vo.
a. vo(t) = 0.3cos(wt)
b. vo(t) = 0.3sin(wt)
c. vo(t) = 3.33cos(wt)
d. vo(t) = 5.0sin(wt)

##### Solution Summary

The solution gives the final answers at first and then explains in detail how each was found, drawing on the theory and equations relevant to near-ideal diode circuits like the one described and the conditions keeping a sinusoidal signal distortion-free.

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Ans:

Maximum value Vs(t)=
(d) Vs(t) = +9sin(wt)

Amplitude of the output signal Vo =
d. vo(t) = 5.0sin(wt)
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Explanation:

When Vo > +5V, D1 gets reverse-biased and so gets turned off while D2 is forward-biased ...

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