Explore BrainMass

Explore BrainMass

    AC/DC BJT transisitor Circuit Analysis

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    For the circuit in the image, Beta=120, VCC=5V, Va=100V, and Rb=25kohms. Determine Vbb and RC such that Rpi=5.4kOhms and the Q-point is in the center of the load line.

    I have a formula for Rpi=(Vt*Beta)/Icq. From this I found Icq=1.25x10^-4 Amps.

    However, is this a correct way to determine Icq? The question said to determine the values such that the Q-point is in the center of the load line. How do I draw the graph to find out the center value if I don't know Vce?

    KVL around to ce loop relates RC and VCE: Rc=(5v-Vce)/(1.25x10^-4) if I can use the Icq from earlier.

    Diagram is attached.

    Please help. What am I missing? Thank you.

    © BrainMass Inc. brainmass.com March 6, 2023, 1:18 pm ad1c9bdddf


    Solution Preview

    The way you got Icq is fine. But the value looks too small. Please check the unit just in case.
    The ...

    Solution Summary

    The solution provides aid and guidance to the problem concerning AC/DC BJT tansistor circuit analysis.