Absolute pressure at depth of water
A submarine is at a depth of 90m below the surface of the sea. Pressure of the atmosphere is 1.03 * 10^5 Pa
What is the absolute pressure at this depth? Density of sea water is 1019kg/m^3
What is the force on a latch of the submarine of dimensions 3m * 4m at this depth?
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Solution Preview
Let P_A = 1.03x10^5 Pa be the atmospheric pressure,
d = 1019kg/m^3 be the density of sea water,
h = 90m be the depth
g = 9.8 m/s^2 be the free fall acceleration
The absolute pressure at this depth is
P = P_A + dgh = 1.03x10^5 Pa + 1019kg/m^3 * 9.8 m/s^2 * 90m ...
Solution Summary
The absolute pressure at depths of water in the sea is determined. The force on a latch of the submarine of dimensions 3m * 4m at this depth is found.
$2.19