# Absolute pressure at depth of water

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A submarine is at a depth of 90m below the surface of the sea. Pressure of the atmosphere is 1.03 * 10^5 Pa

What is the absolute pressure at this depth? Density of sea water is 1019kg/m^3

What is the force on a latch of the submarine of dimensions 3m * 4m at this depth?

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#### Solution Preview

Let P_A = 1.03x10^5 Pa be the atmospheric pressure,

d = 1019kg/m^3 be the density of sea water,

h = 90m be the depth

g = 9.8 m/s^2 be the free fall acceleration

The absolute pressure at this depth is

P = P_A + dgh = 1.03x10^5 Pa + 1019kg/m^3 * 9.8 m/s^2 * 90m ...

#### Solution Summary

The absolute pressure at depths of water in the sea is determined. The force on a latch of the submarine of dimensions 3m * 4m at this depth is found.

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