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Questions Using Planck's Constant

Part 1
An electron microscope operates with a beam of electrons, each of which has an energy of 20 KeV. Use the uncertainty principle in the form delta(x)delta(p) (greater or equal to) h/2 to find the smallest size that such a device could resolve. Planck's constant is 1.0552 × 10^-34 J · s. Answer in units of pm.

Part 2
What must the energy of each neutron in a beam of neutrons be in order to resolve the same size object?
Answer in units of eV.

Part 3
A beam of neutrons with a kinetic energy of 0.0002 eV falls on a slit of width 0.0001 m.
The Planck's constant is 6.63 × 10 ^-34 J · S.
What will be the angular spread of the beam after it passes through the slit?

Answer in units of radian.

Solution Preview

Hi C!

Here are the solutions to this problems set.

However, I must say I'm confused regarding the way the first problem is to be solved. It is stated that it should be solved using the uncertainty principle, while a more reasonable approach is the ...

Solution Summary

This solution provides step by step calculations for various questions involving Planck's constant.