1. A car of mass 1000 kg moves with a speed of 50 m/s on a circular track of radius 100 m. What is the magnitude of its angular momentum (in kg.m^2/s) relative to the center of the racetrack?
2. A Body oscillates with simple harmonicmotion along the x-axis. Its displacement varies with time according to the equation x=5 sin (pie t + pie/3). The velocity (in m/s) of the body at t=1 second is:
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1. The angular momentum is the linear momentum croos-multiplied by the distance vector to the point of refference.
In general, this mean that the magnitude of teh resultant angular momentum is teh multiplication of the magnitudes of ...
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This solution includes explanation and calculations. 170 words.
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... to the sum of the magnitudes of momenta of the ... The two forces are equal in magnitude and opposite ... The total angular momentum is conserved (the total energy is ...
... in an orbit of radius R is equivalent to a current of magnitude eω/2Π ...Angular momentum of a mass going around a circular orbit of radius R with a speed v is ...
... a speed of 50 m/s on a circular track of radius 100 m. What is the magnitude of its angular momentum (in kg.m^2/s) relative to the center of the racetrack? ...
