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The constant angular acceleration of wheels

A wheel is revolving at 20.0 rad/s when a brake is engaged and the wheel is brought to a uniform stop in 15.92 revolutions. How long did it take to stop the wheel and what was the deceleration?

Solution Preview

For 15.92 revolutions, it equals 2pi*15.92=100 rad
First we calculate ...

Solution Summary

After being given the information on the number of revolutions and speed of the wheel, the time in stopping the wheel, as well as its deceleration, were both found in the solution.