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    dynamics and inertia

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    The vehicle s used to transport supplies to and from the bottom of the 25-present grade. Each par of wheels one at A and the other at B has a mass of 140 kg with a radius of gyration of 100 mm. The total mass of the vehicle s 520 g. The vehicle is released from rest with a restraining force T of 500 N n the control cable which passes around the drum and is secured at D. The wheels roll without slipping.
    a) Calculate the inertia of wheel A about its centre in kg.m^2
    b) Calculate the inertia of wheel C about its centre in kg.m^2
    c) Determine the initial acceleration a of the vehicle in m/s^2

    Refer to attachment for diagram

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    Solution Preview

    mass of A, mA = 140 kg
    Radius of gyration, kA = 150 mm == 0.15 m

    inertia I = m*k^2

    inertia of A,
    IA = mA * kA^2 = 140*0.15^2 = 3.15 kg.m^2

    mass of C, mC= 40 kg
    radius of gyration of C, kC = 100 mm = 0.1 m

    Hence, inertia of C,
    IC = mC*kC^2 = 40*0.1^2 = 0.4 kg.m^2

    Vehicle moving downward.
    Let us assume, acceleration of the vehicle = ...

    Solution Summary

    A problem of rolling of a vehicle without slipping is solved.