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Kinematics and Linear Relationships

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Please question #4 completely with detailed solutions and explain 6c with no details left out please (in attached file). From 2 to 4 seconds, the acceleration is positive. Please go from position, to velocity, to acceleration graphs, and determine the changes. Use numbers, explain speeding up and down, and what the curves are doing in each graph.

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The area under the curve of Acceleration vs. Time (diagram attached) is the change in the velocity. However, in this diagram, there is no area under the curve, so there is no change in the velocity. If there is no change in the velocity, then it must remain at the same value as it was, when t=0, or the initial velocity that is ...

Solution Summary

The answer addresses the relationships between velocity, acceleration, time, and position. By looking at the slope of each graphs, and how the x and y values moves, the changes are established.

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One of the most important products that we have in our daily diet is sugar.

One of the most important products that we have in our daily diet is sugar. The main type of sugar that we use is sucrose, which is a disaccharide consisting of glucose and fructose. The hydrolysis of sucrose to produce glucose and fructose occurs by the following overall reaction:

C12H22O11(s) + H2O(l) yields C6H12O6(aq) + C6H12O6(aq)
glucose fructose

A biochemist studies the kinetics of the process and obtains the following data that is consistent with a first order reaction:
[Sucrose]M Time(h)
0.501 0
0.451 0.50
0.404 1.00
0.363 1.50
0.267 3.00

a. Use the above data to determine the rate constant and half-time of the reaction.
b. How long does it take to hydrolyze 70% of the sucrose.
c. How do you explain the fact that other studies demonstrate this is a second order reaction with water as the second reactant? In other words, why isn't water in the rate expression above?

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