Two soccer players start from rest, 49.0 m apart. They run directly toward each other, both players accelerating. The first player has an acceleration whose magnitude is 0.574 m/s2. The second player's acceleration has a magnitude of 0.226 m/s2. (a) How much time passes before they collide? (b) At the instant they collide, how far has the first player run?© BrainMass Inc. brainmass.com October 24, 2018, 6:36 pm ad1c9bdddf
The solution comprises of a concise step by step calculation of determining time before collision and distance traveled in a kinematics problem.
In the discussion of the Lindemann mechanism, it was assumed that the rate of activation by collisions with another reactant molecule, A, was the same with a non-reactant molecule, M, such as an inert gas. What if the rates of activation for these two process are different? In this case, the mechanism become
A +M ?A* + M
A +A ?A* + A
A* ? P
Demonstrate that the rate law expression for this mechanism is:
R= (k3(k1[A][M]+k2[A]^2)/(k-1[M]+k-2[A]+k3)View Full Posting Details