Recurrence Relation
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Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) with the initial conditions a(0)=0 and a(1)=2.
Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) +12 with the initial conditions a(0)=0 and a(1)=2.
For a particular solution, try a(n)=C, a constant.
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Solution Summary
Recurrence relations are solved. The initial conditions for the particular solution is determined.
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