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Recurrence Relation

Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) with the initial conditions a(0)=0 and a(1)=2.

Solve the recurrence relation a(n)=3a(n-1)+10a(n-2) +12 with the initial conditions a(0)=0 and a(1)=2.

For a particular solution, try a(n)=C, a constant.

Solution Summary

Recurrence relations are solved.

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