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Fibonacci sequence in closed form

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Prove that Fn can be expressed by:
Fn=[(a^n-b^n)/(a-b)] for n=1,2,3...

~: Set Gn=[(a^n-b^n)/(a-b)] and show that Gn satisfies the recurrence formula {G(n+1) = Gn + G(n-1) for n=2,3,4...} and don't forget that a and b satisfy the equation x^2-x-1=0.
a and b are the roots of x^2-x-1=0, which are (1+sqrt5)/2 and (1-sqrt5)/2.

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Solution Summary

The Fibonacci sequence in closed forms are given. The recurrence relation is examined.

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This can be easily proved by Mathematical Induction:

We show that the recurrence relationship holds for n = 2 and n=3 by direct substitution:
At n =1 , G(1) =
At n = 2, G(2) = = a + b = 1 (plugging in a ...

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