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    Real Analysis : Proof

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    I need a proof for "If f on [a,b] is continuous & 0 is not a member f([a,b]) then f is bounded away from 0."

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    https://brainmass.com/math/real-analysis/real-analysis-proof-11678

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    I need a proof for "If f on [a,b] is continuous & 0 is not a member f([a,b]) then f is bounded away from 0."

    Proof. Assume that is continuous on [a,b]. Suppose on ...

    Solution Summary

    The statement "If f on [a,b] is continuous & 0 is not a member f([a,b]) then f is bounded away from 0." is proven.

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