Purchase Solution

Real Analysis : Limits and Cluster Points

Not what you're looking for?

Ask Custom Question

Please see the attached file for the fully formatted problems.

1) Prove that does not exist but that .

2) Let f, g be defined on to , and let c be a cluster point of A. Suppose that f is bounded on a neighborhood of c and that .
Prove that .

3) Let f, g be defined on A to and let c be a cluster point of A.

(a) Show that if both and exist, then exists.
(b) If and exist, does it follow that exists?

4) Let f : be such that f(x+y)=f(x)+f(y) for all x, y in . Assume that exists. Prove that L = 0, and then prove that f has a limit at every point . (Hint: First note that f(2x) = f(x)+f(x) = 2f(x) for . Also note that f(x) = f(x - c) + f(c) for x, c in )
---

(See attached file for full problem description)

Attachments
Purchase this Solution

Solution Summary

Limits and Cluster Points are investigated. The solution is detailed and well presented. The response received a rating of "5" from the student who originally posted the question.

Solution Preview

Please see the attached file for the complete solution.
Thanks for using BrainMass.

1) Prove that does not exist but that .
I think the statement should be " Prove that does not exist".
Proof. Let and be two sequences. It is easy to see that

So,
So, does not exist

2) Let f, g be defined on to , and let c be a cluster point of A. Suppose that ...

Solution provided by:
Education
  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
  • "Thank you"
  • "Thank you very much for your valuable time and assistance!"
Purchase this Solution


Free BrainMass Quizzes
Solving quadratic inequalities

This quiz test you on how well you are familiar with solving quadratic inequalities.

Know Your Linear Equations

Each question is a choice-summary multiple choice question that will present you with a linear equation and then make 4 statements about that equation. You must determine which of the 4 statements are true (if any) in regards to the equation.

Graphs and Functions

This quiz helps you easily identify a function and test your understanding of ranges, domains , function inverses and transformations.

Probability Quiz

Some questions on probability

Exponential Expressions

In this quiz, you will have a chance to practice basic terminology of exponential expressions and how to evaluate them.