1 Determine whether the series converges absolutely, converges conditionally, or diverges.
3 Find the interval of convergence of the power series
1. We note that 2*4*6*...*2n = 2^n*n!, then
an = 2*4*6*...*2n / 2^n*(n+2)! = 1/(n+1)(n+2) < 1/n^2
and sum(n from 1 to oo) 1/n^2 is convergent.
Thus the series is convergent. Because this is a positive series,
then it also ...
Convergence of Power Series are investigated.