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    Calculating the limits of a sequence.

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    Use two methods to calculate the limit of the following sequence.

    x(n)=1/n^3+2^2/n^3+...+n^2/n^3

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    Method 1: By using this formula 1+2^2+3^2+...+n^2=n(n+1)(2n+1)/6 we have
    x(n)=1/6*(n+1)(2n+1)/n^2,
    So x(n)->1/3 as ...

    Solution Summary

    The limit of a sequence is calculated.

    $2.49

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