Use two methods to calculate the limit of the following sequence.
x(n)=1/n^3+2^2/n^3+...+n^2/n^3© BrainMass Inc. brainmass.com March 4, 2021, 5:39 pm ad1c9bdddf
Method 1: By using this formula 1+2^2+3^2+...+n^2=n(n+1)(2n+1)/6 we have
So x(n)->1/3 as ...
The limit of a sequence is calculated.