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Calculating the limits of a sequence.

Use two methods to calculate the limit of the following sequence.

x(n)=1/n^3+2^2/n^3+...+n^2/n^3

Solution Preview

Method 1: By using this formula 1+2^2+3^2+...+n^2=n(n+1)(2n+1)/6 we have
x(n)=1/6*(n+1)(2n+1)/n^2,
So x(n)->1/3 as ...

Solution Summary

The limit of a sequence is calculated.

$2.19

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