... is 365/365 (=1). P(2) CANNOT share P(1)'s birthday. ... Tp we just MULTIPLY the individual probabilities. ... This is the probability that N people in a room will all ...

... a) Using Excel, find the birthday problem probabilities for all ... the x-axis = number of randomly chosen people and the y-axis = probability that at ...

... are 6*6*6=216 possible outcomes of their birthdays. So, the probability that none were born on Saturday is ... of them there are 6 possible days for the birthday. ...

... in which each person can have birthdays in different ... Therefore probability that If there are 12 strangers in a ... no two of them celebrate their birthday in the ...

... mean 365 Then the probability that there are no shared birthdays is given by e−13.562 and so the probability that 2 or more senators share a birthday is 1 ...

... 18 and 19: Birthdays Four people are selected at random. Assume 365 days in a year. 18. What is the probability that all four share the same birthday? 19. ...

... 2. The probability that at least two people have the same birthday is 1-P(all of them have different birthdays). There are 365 days in a year, and there are. ...

... Q3). There are 12 strangers in a lecture hall. What is the probability that the 12 persons celebrate their birthdays in 12 different months? Q4). ...

... Number of ways in which 10 students can select different birthdays. ...Probability that each student has a different birthday (that is, no two students have the ...