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Description of Card Probability

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Eight cards are chosen at random from an ordinary deck of 52 cards. What is the probability that exactly one suit is represented among these 8 cards? Exactly 2 suits?

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Question: Eight cards are chosen at random from an ordinary deck of 52 cards. What is the probability that exactly one suit is represented among these 8 cards? Exactly 2 suits?

Solution:
First, there are C(52, 8) = 52! /(8! * 44!) = 752538150 ways to get 8 ...

Solution Summary

In about 170 words, this solution clearly demonstrates through both calculations and explanations, how to compute the card probability related to suit uniformity, which is being asked of in this question.

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