Question: A jar contains 3 white marbles, 2 yellow marbles, 4 red marbles, and 5 blue marbles. Two marbles are picked at random. What is the probability that

a.) Both are blue
b.) Exactly 1 is blue
c.) At least 1 is blue

Solution Preview

(a) The event of choosing 2 marbles has:
14!/(12!2!) = 91 members, corresponding to picking 2 objects out of 14.
The event of choosing 2 blue ones corresponds to choosing 2 blue marbles among 5: 5!/2!3! = 10.
The probability is given by ...

Solution Summary

This solution is comprised of a response of about 175 words which estimates the probability of selecting particular colours of marbles. All calculations which are necessary are illustrated.

... Male Color-Blind 7 44 Not Color-Blind 619 583. ... conditional probability, theorem on total probability, Bayes theorem ... How many different orders for a bagel, cream ...

14 questions: probabilities, expected value, combinations/permutations. ... 9 times and win 2. The probability that he ... x 2 (colors) x 3 (seats) = 12 different bikes. ...

... frame comes in a choice of two colors, red and blue ... a tree diagram illustrating all the different arrangements of ... Use the chart to find the probability that the ...

... such as picking at least one green marble when drawing two marbles at random from a bag containing marbles of different colors, or the probability of two ...

... all of the possible outcomes along with their probabilities. ... at random, what is the probability the they ... bookcases in 5 different sizes and 3 different colors. ...

... frame comes in a choice of two colors, red and blue ... a tree diagram illustrating all the different arrangements of ... Use the chart to find the probability that the ...

... The expert determines the probability of selecting different marbles in multiple ... The colors of the marbles are as follows: red - 5; blue - 8; green - 3 ...

... bag, the probabilities of drawing marbles of different colors are not changed. There are 5 rainbow marbles in the total of 23, so the probability of drawing a ...

... 7*6! = 11*10*9*8*7 = 55,440 different ways (11 ... card is drawn from a deck, find the probability of getting. ... are 52 cards in a deck, so the probabilities are the ...

... can't be larger than the individual probabilities. ... graphs are used to compare different groups or to ... Without replacement, each probability is dependent on what ...