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Local maximum and minimum and saddle points
207113 Local maximum and minimum and saddle points Find the local maximum and minimum values and the saddle points of the functions.
1.)f(x,y)= xy(1-x-y)
2.)f(x,y)= (x^2y^2 - 8x + y)/(xy) see attached
Find the local maximum and minimum values
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Functions: Critical Points, Extrema and Saddle Points
23170 Functions: Critical Points, Extrema and Saddle Points Find the critical points of the given function and classify each as relative minimum, relative maximum, or a saddle point.
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Finding extreme values for functions of two variables
we get:
So the critical points are
, so there is a local minimum at
so there is a saddle point at
so there is a saddle point at
To find the absolute maximum and minimum, if they exist, we have to compare the values with those
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Local maxima, minimum and saddle points
Finding saddle points, minimum and maximum of several functions of two variables.
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Critical Points (Local Maximum, Local Minimum, Saddle Points)
30746 Critical Points (Local Maximum, Local Minimum, Saddle Points) (a) Find all the critical points of f = xy + yz - zx + xyz (Hint: set f = 0)
(b) Classify the critical point of f as local maximum, local minimum or saddle points.
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Maximum, minimum, saddle points
174470 Maximum, minimum, saddle points Please see the attached file.
Find the local maximum and minimum values and saddle point(s) of the function. Please see the attached files.
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Multiple Variable Calculus
This solution has detailed explanations of questions on finding local maxima, minima or saddle points of functions of two variables, directional derivative and gradient vector.
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Maximum and Minimum Values and Saddle Points of f(x,y) = x^3 - 3*x + y^4 - 2*y^2
71887 Maximum and Minimum Values and Saddle Points Use a graph and level curves to estmate the local maximum and minimum values and saddle points of f(x,y) = x^3 - 3*x + y^4 - 2*y^2; then use calculus techniques to find these values precisely.
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Find critical points and test for relative extrema.
to y), then we have 4 cases:
1- AC>B^2 and A>0 -> (a,b) is a local minimum of f
2- AC>B^2 and A<0 -> (a,b) is a local maximum of f
3- ACsaddle point of f
4- AC=B^2 then this test fails and (a,b) may be a local maximum