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Compute the dual prices for given constraints

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The initial probability of success was 1 in 3 or .333. Now the contestant is down to two doors. There is a 50/50 chance of winning with two doors no matter what happened before so it doesn't matter if she switches. (true or false)
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II. The optimal solution of the linear programming problem is at the intersection of constraints 1 and 2.

Max 2x1 + x2
s.t. 4x1 + 1x2 < or equal to 400
4x1 + 3x2 < or equal to 600
1x1 + 2x2 < or equal to 300
x1, x2 > or equal to 0

Compute the dual prices for the tree constraints.
.45, .25, 0
.25, .25, 0
0, .25, .45
.45, .25, .25

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