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    Systems and Nutrition based on aglebra equations

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    Gather nutritional information for two different foods to devise a meal plan that provides optimal nutritional value.

    To maintain health, people need to consume a recommended daily amount of many different vitamins and minerals, as established by government health agencies. To achieve those levels, people have their choice of many types of food to consume. For the sake of simplicity, assume that you are a poor college student who can only afford two items: broccoli and corn. Also assume that the only nutrients you absolutely need to maintain proper health are calcium and iron.

    Gather from credible sources the following data:

    -The amount of calcium and iron (in milligrams) found in one 10 oz package of broccoli
    -The amount of calcium and iron (in milligrams) found in a 1½ cup of frozen corn
    -The recommended daily values (in milligrams) of calcium and iron

    After collecting the data, it should be clear that one 10 oz package of broccoli and one 1½ cup of frozen corn will not allow a person to achieve the minimum levels of calcium and iron for one day. To that end, you need to determine how much of each food item you need in order reach those levels. Construct and solve a linear system of two equations that would make that determination.

    Naturally, people need more than two minerals to survive. Likewise, people eat more than just broccoli and corn. Find four more essential vitamins and minerals and their recommended daily values (in milligrams). Likewise, find four more foods that contain each of the six vitamins and minerals you have listed. Determine that the amount of each nutrient found in one serving of each food.

    Using that information, construct but do not solve a linear system of equations that determines how much of each item a person would need to consume to achieve the recommended daily values of each nutrient.

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    https://brainmass.com/math/linear-algebra/systems-and-nutrition-based-on-aglebra-equations-512374

    Solution Preview

    Located on attachment worksheet 2
    b=10oz of broccoli
    c=half-cup of corn

    calcium equation
    159b + 3.3c = 1000
    b=10oz of broccoli
    c=half-cup of corn

    calcium equation
    159b + 3.3c = 1000

    Iron equation
    2.3b + 0.3c = 18

    modify the equations
    1590b+33c=10000 multiply by 10
    23b+3c=180 multiply by 10

    modify to eliminate c
    3(1590b)+99c=3(10000)
    33(23b)+99c=33(180)

    Subtract the second equation from the first equation and solve for ...

    Solution Summary

    An algebraic approach to gather nutritional information for two different foods to devise a meal plan that provides optimal nutritional value.

    $2.19

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