Recall def. of a < b and show... a + r < b + r
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For any two real numbers a and b, a < b if and only there exist a positive real number s such that a + s = b. Use this definition to prove that for any negative real number r, if a < b then a + r < b + r.
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Solution Summary
The solution uses the definition to prove that for any negative real number r, if a < b then a + r < b + r.
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If a + s = b, where s is positive, then for all negative real r, a + ...
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