Linear Algebra: Factoring, Real and Complex Zeroes
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1. Factor the following polynomial y = 3x4 — 22x3 + 31x2 + 40x —16
2. Find the real solutions of y = x3 + 8x2 + 1 lx — 20
3. Solve the equation in the complex number system. 10x2 + 6x +1= 0
4. Form a polynomial with real coefficients having the given degree and zeros. Degree: 5 Zeros: 1, multiplicity 3; 1 + i
5. Find the complex zeros of the polynomial function f (x) = x4 + 13x2 + 36
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Solution Summary
Linear Algebra problems relating to Factoring, Real and Complex Zeroes are solved.
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Solution.
1. 3x^4-22x^3+31x^2+40x-16=(x+1)(3x-1)(x-4)^2
2. x^3+8x^2+11x-20=(x-1)(x^2+9x+20)=(x-1)(x+4)(x+5)
So there are three real roots x1=1,x2=-4 and x3=-5
3. ...
Education
- BSc , Wuhan Univ. China
- MA, Shandong Univ.
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- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
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