# Homomorphisms

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If $:G->G1 is a homomorphism, show that K = the set of g belonging to G given that $(g)=1 is a subgroup of G (called the kernel of $)

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If G is a group and K is its subgroup, that is K ïƒŒ G, it means that for any a; b ïƒŽ K aâ€¢ b = c ïƒŽ K (where â€¢ is a symbol of the group operation: the group operation does ...

#### Solution Summary

This is a proof regarding homomorphisms and kernels.

$2.49