Explore BrainMass

Explore BrainMass

    volume of solid of revolution

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    1)Figure 11.1: 0<=x<=(pie)/2
    R is bounded below by the x-axis and above by the curve
    y = 2cos(x), Figure 11.1. Find the volume of the solid generated by
    revolving R around the y-axis by the method of cylindrical shells.

    2)Figure 15.1: y= 1/(x^2+4x+5)

    R is the region that lies between the curve (Figure 15.1) and the
    x-axis from x = -3 to x = -1. Find:
    (a) the area of R,
    (b) the volume of the solid generated by revolving R around the y-axis.
    (c) the volume of the solid generated by revolving R round the x-axis.

    © BrainMass Inc. brainmass.com March 4, 2021, 8:20 pm ad1c9bdddf
    https://brainmass.com/math/integrals/volume-of-solid-of-revolution-161348

    Solution Summary

    The solution is a detailed explanation on cylindrical shell method and disk method to find the volume of solid revolving.

    $2.19

    ADVERTISEMENT