# volume of solid of revolution

1)Figure 11.1: 0<=x<=(pie)/2

R is bounded below by the x-axis and above by the curve

y = 2cos(x), Figure 11.1. Find the volume of the solid generated by

revolving R around the y-axis by the method of cylindrical shells.

2)Figure 15.1: y= 1/(x^2+4x+5)

R is the region that lies between the curve (Figure 15.1) and the

x-axis from x = -3 to x = -1. Find:

(a) the area of R,

(b) the volume of the solid generated by revolving R around the y-axis.

(c) the volume of the solid generated by revolving R round the x-axis.

https://brainmass.com/math/integrals/volume-of-solid-of-revolution-161348

#### Solution Summary

The solution is a detailed explanation on cylindrical shell method and disk method to find the volume of solid revolving.

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