Stoke's theorem
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Stoke's theorem is examined.
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Please see the explanations below. Refer to the attachment to see the equations and figure better.
Stoke's Theorem says that the following integrals are equal:
?_S???×F ?dS= ???F?dr??
In other words: The surface integral of the curl of the vector function F is equal to the line integral of the vector field over its boundary.
It looks like for your problem, the surface S is a cube. This Theorem works if one of the sides of the cube is open, so I am going to assume that the bottom edge is open.
see figure in the attached file.
First let's do the surface integral.
We need to calculate the curls of A:
? ×A= |?(i&j&k@?/?x&?/?y&?/?z@A_x&A_y&A_z )|=i((?A_z)/?y-(?A_y)/?z)+j((?A_x)/?z-(?A_z)/?x)+k((?A_y)/?x-(?A_x)/?y)
For the given function:
(?A_z)/?y=0; (?A_y)/?z=y; (?A_x)/?z=-1; (?A_z)/?x=-z; (?A_y)/?x=0; (?A_x)/?y=1
So we have:
i(0 - y) + j(-1 + z) + k(0 - 1) =
? ×A = -y i +(-1 + z) j - k or in vector notation: <-y, -1 + z, -1>
Now, we look at dS in the surface integral.
dS = n ? dA
Where n is the unit normal vector to the ...
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