Use the disk method to find the volume of the solid of revolution formed by revolving the region about the x-axis.
Y = sqrt16-x
Solid region is a semi circle from 0,4 to 16,0 find the solid amount between 5,0 and 6,0.
So, letting f(x) = Sqrt(16-x), of we revolve the given region, around the x-axis, the general formula (Given in any first-year calculus textbook) using the Disc method is:
V = integral(a to b) * pi * [f(x)]^2 dx, where a to b represents ...
This solution finds the volume of the solid of revolution.