Normed Space, Compactness and Transformation
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Let X be a normed space, I closed interval ( or half-open on the right) and
a = inf I, b = sup I.
Let h : I -> [0,infinity) be a continuous function such that
integral ( from a to b ) h(t)dt < positive infinity
where integral from a to b represents the improper integral when I is not closed.
Let epsilon > 0 and X_epsilon,h be the set of all continuous functions f : I -> X such that the number ||f||_e,h defined by
||f||_epsilon,h = (for t in I) sup( e^-(epsilon*integral(from a to t ) h(s)ds)) ||f(t)|| is finite.
Prove that the when the interval I is compact, the set X defined above of normed spaces coincides with C(I,X), and that the sup norm and the norm ||.||_epsilon,h are equivalent. That is, Lim_n x_n = x holds in X_epsilon,h if and only if
lim_n x_n = x uniformly.
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Mathematics, Ordinary Differential Equations
systems of equations as transformations
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Let X be a normed space, I closed interval ( or half-open on the right) and
a = inf I, b = sup I.
Let h : I -> [0,infinity) be a continuous function such that
integral ( from a to b ) h(t)dt < positive infinity
where integral from a to b represents the improper integral when I is not closed.
Let epsilon > 0 and X_epsilon,h be the set of all continuous functions f : I -> X such that the number ||f||_e,h defined by
||f||_epsilon,h = (for t in I) sup( e^-(epsilon*integral(from a to t ) h(s)ds)) ||f(t)|| is finite.
Prove that the when the interval I is compact, the set X defined ...
Purchase this Solution
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