19. ∫0 to (pi/4) of x²cos x dx
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F = ∫x2 (d sin(x)/ dx) dx
= x2 sin(x) - ∫2x sin(x) dx
= x2 sin(x) - 2∫x sin(x) dx
= x2 sin(x) - 2∫x (-cos(x)') dx
An integral is solved. The response received a rating of "5" from the student who posted the question.