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    Evaluate the following integrals:
    (1)The integral of (6sin[2x])/sin(x)dx=____+C
    (2)The integral of (7-x)(3+[x^2])dx=____+C
    (3)The integral from 3 to 7 of ([t^6]-[t^2])/(t^4)dt=____+C
    (4)The integral of (6sin[x])/(1-sin^2[x])dx=____+C

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    Solution Preview

    sin(2x)=2sin(x)cos(x) ---> 6sin(2x)/sin(x)= 12cos(x) and thereforte the integral is:


    Mulitply the terms:
    (7-x)(3+x^2)= ...

    Solution Summary

    This shows how to evaluate integrals with fractions and sine functions.