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    Contour Integrals

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    Prove that integral (0 to pi/2) of sin^2n theta d(theta)=pi(1x3x5x...2n-1)/2(2x4x6x...2n)

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    Prove that integal(o to pi/2) of sin^2n theta d(theta)=pi(1x3x5x...2n-1)/2(2x4x6x...2n)

    Proof. ...

    Solution Summary

    A contour integral is found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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