# Contour Integrals

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Prove that integral (0 to pi/2) of sin^2n theta d(theta)=pi(1x3x5x...2n-1)/2(2x4x6x...2n)

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Prove that integal(o to pi/2) of sin^2n theta d(theta)=pi(1x3x5x...2n-1)/2(2x4x6x...2n)

Proof. ...

#### Solution Summary

A contour integral is found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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