#1) Find the vertex and intercepts of function f(x)=x^2+x-2.
#2) Graph the linear equation y=2/3(x)-2
#3) Find the x and y intercepts of 4x+3y=-12
1) if f(x) = 0 then x^2 + x - 2 = 0. This equation can be factored (x+2)(x-1) so, when graphed, if y = 0, x = -2, 1 (these are the x-intercepts). If x = 0 then f(x) = 0+0-2 = -2 (this is the y-intercept). To find the vertex, you can use the formula h = -b/2a so for this function h = -1/2*1 = -1/2. Substituting ...
There are a variety of problems here, including finding intercepts and slope, parallel lines, and graphing.