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Consistent and Dependent Functions and Graphing

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. Determine whether the system is consistent, inconsistent, or dependent.
3x + 2y = 15
6x + 4y = 30 (Points : 1)
Consistent
Dependent
Inconsistent

7. Carla invested $23,000, part at 16% and part at 15%. If the total interest at the end of the year is $3,500, how much did she invest at 16%? (Points : 1)
$4,000
$18,000
$6,000
$5,000

8. Find the coordinates of the x-intercept.
2x + y = -6 (Points : 1)
(-6, 0)
(0, -3)
(0, -6)
(-3, 0)

9. Determine whether the system is consistent, inconsistent, or dependent.
3x - 3y = -9
9x - 9y = -27 (Points : 1)
Consistent
Dependent
Inconsistant

10. The amount of revenue a company makes per day by selling x items is given by the function f(x) = 14x - 0.2x2. How many items should be sold if the company wants to maximize their profit? (Points : 1)
30 items
35 items
70 items
40 items

11. Find the domain and range of the relation, and state whether or not the relation is a function.
{(7, 2), (8, 2), (9, 2), (10, 2)} (Points : 1)
Domain = {2}, Range = {7, 8, 9, 10}
The relation is not a function.
Domain = {2}, Range = {7, 8, 9, 10}
The relation is a function.
Domain = {7, 8, 9, 10}, Range = {2}
The relation is not a function.
Domain = {7, 8, 9, 10}, Range = {2}
The relation is a function.

12. Write the equation in the slope-intercept form.
4x - 10y = 11 (Points : 1)
y = 2/5x - 11
y = -2/5x + 11/10
y = -2/5x + 11
y = 2/5x - 11/10

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Solution Summary

Herein are solutions to a variety of algebra problems associated with consistent functions, graphing, and interest. Full work is shown when necessary, and explanations are given.

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. Determine whether the system is consistent, inconsistent, or dependent.
3x + 2y = 15
6x + 4y = 30 (Points : 1)
Consistent
Dependent
Inconsistent

This is dependent because they are the same line, so infinite number of solutions

7. Carla invested $23,000, part at 16% and part at 15%. If the total interest at the end of the year is $3,500, how much did she invest at 16%? (Points : 1)
$4,000
$18,000
$6,000
$5,000

We can set up a system of equations ...

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