... The equation of tangent line with slope -1/8 will be 1 y = − x+b 8 We will find b by using the fact that tangent line passes through the point (4, ½). ...
... By part a), we know that the equation of the tangent line is 2ax-y+8a=0 So, let x=0, we get y=8a So, the y intercept of the tangent line at x = -1 is 8a. ...
Implicit differentiation, equation of the tangent line. ... It shows how to find the derivative and equation of tangent line by implicit differentiation. ...
... Therefore, the tangent line equation is y − f (8) = m( x − 8). Now find f (8) = (2 *8 + 4)2 − (2 * 8 − 4) 2 = 256. So the equation of the tangent line is. ...
... 5, −1) is −3/2. Now we can use this slope and the coordinates of the point (5, −1) to get the pointslope form of the equation of that tangent line: ...
... c) Find the equation of the tangent line to the graph of f at the point (3,2/-3). Write your answer in the form y=mx+b. The equation of the tangent line to the ...
Equation of the Line Tangent to the Curve. Hi, this was your response. ...Equation of the line tangent to the curve= dy/dx = 3x^2 - 12x. Thanks Ramesh. ...
Equation of a straight line which is tangent to a curve. ... Finds the equation of the straight line which is tangent to the curve f(x) = x - 1/3x^2. ...
