Explore BrainMass

Explore BrainMass

    Subgroup proof

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Prove: any subgroup of the order of p^(n-1) in a group of order p^n, where p is a prime, is a normal subgroup

    © BrainMass Inc. brainmass.com March 4, 2021, 5:59 pm ad1c9bdddf
    https://brainmass.com/math/discrete-math/subgroup-proof-21828

    Solution Preview

    Proof: Suppose G is a group with order |G|=p^n. H is a subgroup of G with order |H|=p^(n-1). p is a prime. Now we show that H is a normal subgroup.
    We consider N(H)={x|x ...

    Solution Summary

    This is a proof regarding normal groups

    $2.19

    ADVERTISEMENT