Epimorphism proof
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Prove: A group G is the union of 3 proper subgroups iff there exists an epimorphism between G and the Klein 4-group.
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Solution Summary
This provides an example of proving a union between proper subgroups.
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Equivalently, a group is a union of three proper subgroups iff it has a quotient isomorphic to C_2 x C_2.
Observe that C_2 x C_2 is already a union of three of its proper subgroups, namely:
H_1 = <(1, 0)>
H_2 = <(0, 1)>
H_3 = <(1, 1)>;
so if there is a surjective homomorphism f : G --> C_2 x C_2, we have
G = f^{-1} (C_2 x C_2) = f^{-1} (H_1) U f^{-1}(H_2) U f^{-1} (H_3)
We prove the converse under the additional assumption that G is finite. So, assume that G can be written as
a union of 3 proper subgroups A, B, C. Notice that any one of these subgroups cannot be contained in the union
of the other two, for otherwise G is a union of two proper subgroups, impossible.
Now, ...
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