Slope of a tangent line and derivatives

Related BrainMass Solutions

• Tangent and normal lines

  So, the slope of the tangent line is k=y'(0)=2 So, the slope of the normal line is k'=-1/k=-1/2 Therefore, the equation of the tangent line is y-2=2(x-0) i.e., y=2x+2; and the equation of the normal line

• Derivatives and Tangent Lines

  165592 Derivatives and Tangent Lines 3. Answer these questions. a. Find f'(x) where f(x)= 3x4 + 2 - b. Find the equation of the tangent line at x=1 for the function f(x) from part a. c.

• Slope of a tangent line and derivative

  316839 Slope of a tangent line and derivatives Find the slope and the equation of the tangent line to the graph of the function at the given value of x. f(x) = x^4 - 5x^2 + 4 x = -2 The slope of the tangent line = ?

• Derivative applications

  Slope of tangent line = slope of secant line = But slope of tangent = f'(x) = x*(1/x) + ln x = ln x + 1 Therefore, ln x + 1 = Or ln x = 1 - = Or x = exp At x = exp , f(x) = exp Therefore, the point of tangency is (x, y) given above.

• implicit differentiation

  This solution is comprised of a detailed explanation to use implicit differentiation to find the slope of the tangent line to the curve at the point .

• Derivatives and Tangent Lines (8 Problems)

  the Tangent Line at the Given Point. 7) x³ - 4y² = 4 at ( 2,1) Take derivative on both sides, we have So, at point P(2,1), we have So, the slope of the tangent line is k=3/2 So, its

• Differientiate the function and tangent line

  4) The slope of the tangent line is the derivative of the function.

• Derivatives and Tangent Lines

  The equation of a tangent line is found.

• Derivatives, Limits and Equation of Tangent Lines

  Step-by-step solutions to the derivatives, limits and equation of tangent lines.