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    Finding critical points, extreme values and saddle points. f(x,y)=x3+3xy2-3x2-3y2+4.

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    Given f(x,y)=x3+3xy2-3x2-3y2+4. Find all critical points of f and find extreme values (maxima and minima) and saddle points of f.

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    To find the critical point of ...

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    Critical points, extrema and saddle points are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.