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    Working with Trignometric identities

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    Sec0 * cos 2*0 = 2*cos0 - sec0

    © BrainMass Inc. brainmass.com December 24, 2021, 4:53 pm ad1c9bdddf
    https://brainmass.com/math/complex-analysis/working-trigonometric-identities-13613

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    Response : PC 13613
     
    LHS = sec(0)* cos2(0)
    we know that cos^2(0) = (1 + cos2(0))/2
    Therefore, cos2(0) = 2cos^2(0) -1
    It implies, LHS = sec(0) * (2cos^2(0) - 1)
    also, sec(0) = 1/cos(0)
    => LHS = 2cos(0) - sec(0) = RHS
    which is the required result.
     
    0 = theta

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 4:53 pm ad1c9bdddf>
    https://brainmass.com/math/complex-analysis/working-trigonometric-identities-13613

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