Working with Trignometric identities
Not what you're looking for? Search our solutions OR ask your own Custom question.
Sec0 * cos 2*0 = 2*cos0 - sec0
© BrainMass Inc. brainmass.com December 24, 2021, 4:53 pm ad1c9bdddfhttps://brainmass.com/math/complex-analysis/working-trigonometric-identities-13613
SOLUTION This solution is FREE courtesy of BrainMass!
Response : PC 13613
Â
LHS = sec(0)* cos2(0)
we know that cos^2(0) = (1 + cos2(0))/2
Therefore, cos2(0) = 2cos^2(0) -1
It implies, LHS = sec(0) * (2cos^2(0) - 1)
also, sec(0) = 1/cos(0)
=> LHS = 2cos(0) - sec(0) = RHS
which is the required result.
Â
0 = theta
https://brainmass.com/math/complex-analysis/working-trigonometric-identities-13613