Verifying that Complex Numbers are Solutions to an Equation

Related BrainMass Solutions

• Solutions of relations on the complex numbers

  Thus all complex numbers of the form z = x + yi for which x = -1 are solutions of this equation. That is, y can be ANY real number, but x must be equal to -1.

• Mathematics - Algebra - Quadratic Equations

  Type an integer or a decimal. Round to the nearest tenth.) 27. Write a quadratic equation in the variable x having the given numbers as solutions.

• Algebra

  Express complex numbers in terms of i. use a comma to separate answers as needed) A. Solve B. Find the x-intercepts of a) what are the solutions? X=________________ (type an exact answer, using radicals as needed.

• The discriminant of the quadratic equation and parabola

  Geometrically, this means that the parabola intersects the x-axis in two points. (3) If the discriminant is negative, there are two different solutions x, both of which are complex numbers. The two solutions are complex conjugates of each other.

• Real-Life Applications of Complex or Imaginary Numbers

  However, in the complex numbers there are, so one can find all complex-valued solutions to the equation (*), and then finally restrict oneself to those that are purely real-valued.

• Verifying Trigonometric Identities

  Observe that the roots are complex and , . Hence the roots can also be expressed as and . Hence the general solution of the recurrence relation is given by Where are arbitrary constants.

• 20 Quadratic Equation Questions : Word problems and Complex Roots

  nonreal complex numbers.

• Using the quadratic formula to solve quadratic equations

  167492 Using the quadratic formula to solve quadratic equations Is it true that solutions to quadratic equations can always be found using the quadratic formula?

• Quadratic Equation

  If they are complex, then certain behaviors can be expected. These are often just the solutions that one wants.

• Imaginary ( Complex ) Numbers, Discriminants and Real World Applications

  The solutions to the equation will then be complex numbers (i.e., involve the imaginary unit i). Question: In the real world, where might these so-called imaginary numbers be used? 2.