Explore BrainMass

Explore BrainMass

    Fields, Elements and Cyclic Groups

    Not what you're looking for? Search our solutions OR ask your own Custom question.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Find H K in {see attachment}, if H = <|3|> and K = <|5|>.

    This is all the problem says. I know the answer, but I do not know the reasoning.

    © BrainMass Inc. brainmass.com December 24, 2021, 5:08 pm ad1c9bdddf


    Solution Preview

    Please see the attached file for the complete solution.
    Thanks for using BrainMass.


    Z16* is the set of Z16, without the element [0] and the operation figured out is the multiplication.
    That means the set contains the elements [1], [2],...[15].
    <|3|> is the cyclic group generated by the element [3]
    This group is:
    H = {[1], [3], [9], ...

    Solution Summary

    Fields, Elements and Cyclic Groups are investigated. The solution is detailed and well presented.