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    Test for convergence or divergence, absolute or conditional.

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    Test for convergence or divergence, absolute or conditional. If it converges, then find the sum too.

    Sigma, infinity over and n=0 under times

    [1/n+2 - 1/n+1 ]

    (this is fraction 1/n+2 minus fraction 1/n+1)

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    https://brainmass.com/math/calculus-and-analysis/test-convergence-divergence-absolute-conditional-8806

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    1/n+2 - ...

    Solution Summary

    A summation is proven to be convergent. The expert tests for convergence or divergence, absolute or conditional.

    $2.19

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