# Find ds/d? for the curves : r2 = a2cos2? etc.,

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Tangent and Normal (II)

(Differential Calculus)

Find ds/d? for the curves : (a) r2 = a2cos2? (b) rn = ancosn?

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This solution is comprised of a detailed explanation for finding ds/d? of curves.

It contains step-by-step explanation for finding ds/d? for the curves :

(a) r2 = a2cos2? (b) rn = ancosn?

Solution contains detailed step-by-step explanation.

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Tangent and Normal (II)

(Differential Calculus)

Written by :- Thokchom Sarojkumar Sinha

Find ds/dθ for the curves : (a) r2 = a2cos2θ (b) rn = ancosnθ

Soluion :- (a) r2 = a2cos2θ

We know that ds/dθ = √[r2 + (dr/dθ)2] -------------------------(1)

Differentiating the equation r2 = a2cos2θ with respect to 'θ' , we get

2r dr/dθ = a2 (- sin 2θ).2 = - 2a2sin2θ

or, dr/dθ = - a2sin2θ/r

Using this value in (1) , we get

ds/dθ = √[r2 + (- a2sin2θ/r)2] = √[r4 + a4sin22θ]/r

= ...

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- BSc, Manipur University
- MSc, Kanpur University

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