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# Epsilon-delta limits

Show that: lim (x+y)=o as x and y approach zero; using the epsilon-delta definition

Also, show that: lim f(x)=1 as x approaches zero; using the epsilon-delta definition.
**Note: x is a vector in this case, with a right arrow going over it. It is not just "x".

#### Solution Preview

Hello,

We have a function f(x,y) = (x+y), and we need to show that:

Lim f(x,y) = Lim (x + y) = 0
x -> 0 x -> 0
y -> 0 y -> 0

First we need to define and understand what is meant by limit.

Definition:
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A function f(x,y) tends to limit L as x tends to a, and y tends to b if and only if:

For each real number epsilon > 0, there can be found a real number delta > 0 such that the following statement is always true:

If:
|x - a| < delta and |y - b| < delta and (x,y) is not equal to (a,b) (1)

then:
| f(x,y) - L | < epsilon (2)
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So for our problem, we can write:

Lim (x + y) = 0
x -> 0
y -> 0

if and only if for each epsilon > 0, we can find a delta > 0 such that the following statement is true:

If: |x| < delta and |y| < delta and (x,y) is not equal to (0,0) (3)

then: |x + y - 0| < epsilon (4)

So the challenge we have to meet is this: If someone was to give us any real number epsilon > 0 (no matter how small) we must be able to assure them that we will definitely be able to give them back a delta > 0 such ...

#### Solution Summary

This shows how to find limits using epsilon-delta.

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