... Since there definitely is an absolute max and an absolute min, if we can find the location of all the critical points, then simply comparing the values of the ...
... Answer: f has a critical point at x = 1 exactly when k = _____. ... Answer: f has a relative maximum at x = 1 exactly when k ... (c) If f has a relative minimum at x = 1 ...
... (b) For critical points, we need to know the values of where the function takes the maximum/minimum values So, let 1/4sin2(theta) = 1/4. => sin2(theta) =1 ...
... finding local maximum/minimum of a function. It also explains how to apply Rolle's Theorem and Mean value Theorem. 1. find all of the critical points and local ...
...Critical points are x = 0, 5. Since g"(0) < 0 so g(x) will have local maximum at x = 0. Since g"(5) > 0 so g(x) will have local minimum at x = 5. ...
... 5 The function f(x)=x^4 4x^3 + 8x has a critical point at x ... 1. Use the second derivative test to identify it as a local maximum, a local minimum or neither ...
... To find critical points, put g'(x) = 0 -2x+11 = 0. ... x) at x = 11/2 and also at the end points of the ... Thus, function has absolute maximum at x =11/2 and its value...
