# Word problem with fractions

A survey of college sophomores showed that 5/6 of the males were taking a mathematics class and 3/4 of the females were taking a mathematics class. One-third of the males were enrolled in calculus, and 1/5 of the females were enrolled in calculus. If just as many males as females were surveyed then what fraction of the surveyed students taking mathematics were enrolled in calculus? Rework this problem assuming that the number of females in the survey was twice the number of males.

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## SOLUTION This solution is **FREE** courtesy of BrainMass!

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1) Let N be the number of male and females surveyed.

Total number of students talking A math. class = N * [ 5/6 + 3/4 ] = 19/12 N

Total number of students talking A Calculus class = N * [ 1/3 + 1/5 ] = 8/15 N

Hence, the Fraction = (8/15)/(19/12) = 0.34

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2) Let N be the number of males and 2N be the number of females surveyed.

Total number of students talking A math. class = N * [ 5/6 + 2*3/4 ] = 11/6 N

Total number of students talking A Calculus class = N * [ 1/3 + 2/5 ] = 11/15 N

Hence, the Fraction = (11/15)/(6/11) = 0.4

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